DRAFT: This module has unpublished changes.

Sample Calculation:

 

A 5.40 g sample of hydrated sodium sulfate, Na2SO4 . xH2O, was found to contain 2.34 g of anhydrous Na2SO4 . This means that the sample had 3.06 g of water (5.40 g - 2.34 g).

 

Water Content of the Sample:

 

(3.06 g H2O)     x 100 = 56.7% H2O

(Na2SO4 . xH2O)

 

Molar Ratio Between Na2SO4 and  H2O :

 

Na2SO4 : (2.34 g Na2SO4 )     = 0.0165 mol Na2SO4

            (142 g/mol Na2SO4)

 

H2O : (3.06 g H2O)        = 0.170 mol H2O

        (18.02 g/mol H2O)

 

Molar Ratio: (0.0165 mol Na2SO4)  : (0.170 mol H2O)     = (ratio below)

                 (0.0165 mol Na2SO4)  (0.0165 mol Na2SO4)

                                                                    

Molar Ratio: 1.00 mol Na2SO4  : 10.3 mol H2O

                                                                            

 

DRAFT: This module has unpublished changes.