DRAFT: This module has unpublished changes.

Calculations:

 

Concentration of NaOH Solution (M):

 

The concentration of the NaOH solution was determined to be 0.097 M in lab 6a.

 

Amount of NaOH to Reach the Equivalence Point (mol):

 

Trial 1:

 

0.097 M NaOH x 0.015080 L NaOH = 0.00151 mol NaOH

                

Trial 2:

 

0.097 M NaOH x 0.016542 L NaOH = 0.00165 mol NaOH

 

Trial 3:

 

0.097 M NaOH x 0.015973 L NaOH = 0.00160 mol NaOH

 

 

Amount of HCl in the Solution (mol):

 

Values are equal to the number of moles of NaOH required to reach the equivalence point, because NaOH and HCl react in a 1:1 molar ratio.

 

 

 

Volume of NaOH Solution to Reach the Equivalence Point (mL):

 

 

 

 

Values are Taken from the Attached Graphs (See Above):

 

Trial 1: 15.080 mL

 

Trial 2: 16.542 mL

 

Trial 3: 15.973 mL

 

Concentration of the HCl Solution (M):

 

Trial 1:

 

0.00151 mol HCl = 0.0755M HCl

0.0200 L HCl

 

Trial 2:

 

0.00165 mol HCl = 0.00825 M HCl

0.0200 L HCl 

 

Trial 3:

 

0.00160 mol HCl = 0.0800 M HCl

0.0200 L HCl 

 

Average Concentration of the HCl Solution (mol/L):

 

0.0755 M + 0.00825 M + 0.0800 M = 0.0546 M HCl

                      3

DRAFT: This module has unpublished changes.