Calculations:

 

 

Number of Moles of KHP (mol):

 

Trial 1:

 

0.217 g KHP x   1 mol KHP      = 0.00106 mol KHP

                       204.227 g KHP

 

Trial 2:

 

0.203 g KHP x   1 mol KHP      = 0.000939 mol KHP

                       204.227 g KHP

 

Trial 3:

 

0.202 g KHP x   1 mol KHP      = 0.000989 mol KHP

                       204.227 g KHP

 

Number of Moles of NaOH that can React the KHP (mol):

 

Values are equal to the number of moles of KHP, because NaOH and KHP react in a 1:1 molar ratio.

 

 

 

Volume of Titrant to Reach the Equivalence Point (mL):

 

Graphs:

 

  

 

 

 

 

 

Values are Taken from the Attatched Graphs (Shown Above):

 

Trial 1: 11.602 mL

 

Trial 2: 10.475 mL

 

Trial 3: 9.467 mL

 

 

Concentration of NaOH Solution (mol/L):

 

Trial 1:

 

0.00106 mol NaOH = 0.091 M NaOH

0.011602 L NaOH

 

Trial 2:

 

0.000939 mol NaOH = 0.095 M NaOH

0.010475 L NaOH

 

Trial 3:

 

0.000989 mol NaOH = 0.104 M NaOH

0.009467 L NaOH

 

 

Average Concentration of NaOH Solution (mol/L):

 

0.091 M + 0.095 M + 0.104 M = 0.097 M NaOH

                      3