Calculations:
Calculate the formula weight of the solute:
Trial 1:
(3.90 K Kg) x ___(0.5060 g) = 87.469 _g_
mol ((2.8 K)(0.008055 Kg)) mol
Trial 2:
(3.90 K Kg) x ___(1.0126 g) = 109.017 _g_
mol ((4.5 K)(0.008055 Kg)) mol
Calculate the number of moles of the solute used:
Trial 1:
0.5060 g = 0.00578 mol
87.496 g
mol
Trial 2:
1.0126 g = 0.0093 mol
109.017 g
mol
Calculate the molality of the solution using the number of moles:
Trial 1:
CR= 0.00578 mol = 0.718 m
0.008055 Kg
Trial 2:
CR= 0.0093 mol = 1.153 m
0.008055 Kg
Percent Error (Trial 1):
122.4 - 87.496 x 100 = 28.52%
122.4
Graphs:
Graph 1: Temperature vs. Time