DRAFT: This module has unpublished changes.

Calculations:

 

 

Calculate the formula weight of the solute:

 

Trial 1:

 

(3.90 K Kg)   x   ___(0.5060 g)          = 87.469 _g_

          mol       ((2.8 K)(0.008055 Kg))             mol

 

Trial 2:

 

(3.90 K Kg)   x   ___(1.0126 g)          = 109.017 _g_

          mol       ((4.5 K)(0.008055 Kg))                mol

 

 

 

Calculate the number of moles of the solute used:

 

Trial 1:

 

0.5060 g  = 0.00578 mol

87.496

          mol

 

Trial 2:

 

1.0126 g    = 0.0093 mol

109.017 

           mol

 

 

 

Calculate the molality of the solution using the number of moles:

 

Trial 1:

 

CR= 0.00578 mol  = 0.718 m

       0.008055 Kg

 

Trial 2:

 

CR= 0.0093 mol  = 1.153 m

       0.008055 Kg

 

 

 

Percent Error (Trial 1):

 

122.4 - 87.496   x 100 = 28.52%

       122.4

 

 

Graphs:

 

Graph 1: Temperature vs. Time

 

DRAFT: This module has unpublished changes.