DRAFT: This module has unpublished changes.

Sample Calculations:


Concentration of NaOH Solution (M):

The concentration of the NaOH solution was determined to be 0.097 M in Lab 6a: Standardizing a Solution of Sodium Hydroxide.

 


Volume of NaOH solution to reach the equivalence point (mL):

Taken from the graphs below


Trial 1: 10.844 mL

Trial 2: 9.438 mL

Trial 3: 4.144 mL



Amount of NaOH to reach the equivalence point (mol)

Trial 1

Trial 2

Trial 3




The excess amount of HCl removed by the added NaOH (mol)

Because HCl and NaOH react in a 1:1 molar ration, the excess amount of HCl removed by the added NaOH is the same as the number of moles of NaOH needed to reach the equivalence point.



Concentration of the HCl solution (M)

The concentration of the HCl was determined to be 0.0793 M in Lab 7a: Acid-Base Titration.



Total amount of HCl added to the solution (mol)



Amount of HCl used by CaCO3 (mol)

Trial 1

Trial 2

Trial 3



Amount of CaCO3 in the sample (g)

Trial 1

Trial 2

Trial 3



CaCO3 content the sample (%)

Trial 1

Trial 2

Trial 3



Average CaCO3 content in the sample (%) 



DRAFT: This module has unpublished changes.