Table 1: Determine the concentration of the HCl solution
|
Parameter |
Trial 1 |
Trial 2 |
Trial 3 |
|
Concentration of NaOH solution (M) |
0.0972 M |
0.0972 M |
0.0972 M |
|
Volume of NaOH solution to reach the equivalence point (mL) |
8.116 mL |
5.266 mL |
5.748 mL |
|
Amount of NaOH to reach the equivalence point (mol) |
7.88x10^-4mol |
5.11x10^-3 mol |
5.58x10^-3 mol |
|
The excess amount of HCl removed by the added NaOH (mol) |
7.88x10^-4mol |
5.11x10^-3 mol |
5.58x10^-3 mol |
|
Concentration of the HCl solution (mol) |
0.081 mol |
0.081 mol |
0.081 mol |
|
Total amount of HCl added to solution (mol) |
0.0081 mol |
0.0081 mol |
0.0081 mol |
|
Amount of HCl used by CaCO3 in the sample (mol) |
7.70*10^-3 mol |
2.9*10^-3 mol |
2.5*10^-3 mol |
|
Amount of CaCO3 in the sample (mol) |
3.94x10^-4 mol |
1.45x10^-3mol |
1.25x10^-3 mol |
|
Amount of CaCO3 in the sample (g) |
0.0394g |
0.1451g |
0.125g |
|
CaCO3 content the sample (%) |
3.94% |
14.51% |
12.51% |
|
Average CaCO3 content the sample (%) |
|
10.32% |
|